# No Schauder Base in $\ell^\infty$

In a recent post about $\ell^\infty$, I’ve said that there’s a more direct way to show that a Schauder base doesn’t exist in $\ell^\infty$. This proof can be found on Math Stack Exchange. It uses three facts.
1. $c_0$ is closed.
3. $x^*$ is continous.